Ethyl amine and aniline can be distinguished | vedclass

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Question

(A) Ethyl amine $(CH_3CH_2NH_2)$ is an aliphatic amine,while aniline $(C_6H_5NH_2)$ is an aromatic amine.$1$. $Br_2/H_2O$: Aniline reacts with bromine

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$Br_2/H_2O$

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(A) Ethyl amine $(CH_3CH_2NH_2)$ is an aliphatic amine,while aniline $(C_6H_5NH_2)$ is an aromatic amine.$1$. $Br_2/H_2O$: Aniline reacts with bromine water to form a white precipitate of $2,4,6$-tribromoaniline,whereas ethyl amine does not show this reaction.$2$. $CHCl_3/KOH$: Both undergo the carbylamine test,but the test is generally used to distinguish primary amines from secondary/tertiary amines,not specifically aliphatic from aromatic.$3$. $C_6H_5SO_2Cl$ (Hinsberg's reagent): Both react,but the solubility of the resulting sulfonamide in alkali differs due to the nature of the substituents.However,$Br_2/H_2O$ is the most characteristic test to distinguish between aliphatic and aromatic primary amines.

List-$I$ (Test)	List-$II$ (Characteristic group)
$A.$ Carbylamine test	$I.$ Phenol
$B.$ Bayer's test	$II.$ Acetone
$C.$ Iodoform test	$III.$ Ethylene
$D.$ Phthalein dye test	$IV.$ Aniline

Ethyl amine and aniline can be distinguished by

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Match List-$I$ with List-$II$:
List-$I$ (Test) List-$II$ (Characteristic group)
$A.$ Carbylamine test $I.$ Phenol
$B.$ Bayer's test $II.$ Acetone
$C.$ Iodoform test $III.$ Ethylene
$D.$ Phthalein dye test $IV.$ Aniline
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$p$-toluenesulphonyl chloride is known as Hinsberg's reagent. Which of the following statements is $NOT$ correct for it?

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