Ethyl ester xrightarrow{CH_3MgBr text{ (exces | vedclass

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(A) The reaction of an ethyl ester $(R-COOC_2H_5)$ with excess Grignard reagent $(CH_3MgBr)$ proceeds as follows:$1$. The first equivalent of $CH_3MgB

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(A) The reaction of an ethyl ester $(R-COOC_2H_5)$ with excess Grignard reagent $(CH_3MgBr)$ proceeds as follows:$1$. The first equivalent of $CH_3MgBr$ attacks the carbonyl carbon of the ester to form a tetrahedral intermediate,which then eliminates the ethoxide ion $(C_2H_5O^-)$ to form a ketone $(R-COCH_3)$.$2$. The second equivalent of $CH_3MgBr$ immediately attacks the newly formed ketone to produce an alkoxide intermediate.$3$. Upon acidic workup $(H_3O^+)$,the alkoxide is protonated to yield a tertiary alcohol of the structure $R-C(OH)(CH_3)_2$.Thus,the product $P$ is a tertiary alcohol containing two methyl groups attached to the carbon atom that also bears the hydroxyl group.

Ethyl ester $\xrightarrow{CH_3MgBr \text{ (excess)}} P$. The product $P$ will be

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