Evaluate the following:sin 60^{circ} cos 30^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given expression is $\sin 60^{\circ} \cos 30^{\circ} + \sin 30^{\circ} \cos 60^{\circ}$.Using the standard trigonometric values:$\sin 60^{\cir

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The given expression is $\sin 60^{\circ} \cos 30^{\circ} + \sin 30^{\circ} \cos 60^{\circ}$.Using the standard trigonometric values:$\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,$\cos 30^{\circ} = \frac{\sqrt{3}}{2}$,$\sin 30^{\circ} = \frac{1}{2}$,and $\cos 60^{\circ} = \frac{1}{2}$.Substituting these values into the expression:$= \left(\frac{\sqrt{3}}{2}\right) \left(\frac{\sqrt{3}}{2}\right) + \left(\frac{1}{2}\right) \left(\frac{1}{2}\right)$$= \frac{3}{4} + \frac{1}{4}$$= \frac{3 + 1}{4} = \frac{4}{4} = 1$.

Evaluate the following:
$\sin 60^{\circ} \cos 30^{\circ} + \sin 30^{\circ} \cos 60^{\circ}$

Similar Questions

Write 'True' or 'False' and justify your answer.
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

For acute angle $\theta,$ if $\cos \theta = \sin \theta,$ then $2 \tan^{2} \theta + \sin^{2} \theta + 1 = \ldots$

$\frac{2 \tan 30^{\circ}}{1-\tan ^{2} 30^{\circ}} = ?$

$\sin 2A = 2 \sin A$ is true when $A =$ (in $^{\circ}$)

Express $\sin 67^{\circ} + \cos 75^{\circ}$ in terms of trigonometric ratios of angles between $0^{\circ}$ and $45^{\circ}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Evaluate the following:$\sin 60^{\circ} \cos 30^{\circ} + \sin 30^{\circ} \cos 60^{\circ}$