मान ज्ञात कीजिए: (cos 252^{circ} - sin 126^{c | vedclass

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(B) हल: $E = (\cos^2 252^{\circ} - \sin^2 126^{\circ})(\sin^2 126^{\circ} + \sin^2 186^{\circ} + \sin^2 66^{\circ})$.$\cos^2 	heta = \frac{1+\cos 2

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$\frac{-3 \sqrt{5}}{8}$

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(B) हल: $E = (\cos^2 252^{\circ} - \sin^2 126^{\circ})(\sin^2 126^{\circ} + \sin^2 186^{\circ} + \sin^2 66^{\circ})$.$\cos^2 	heta = \frac{1+\cos 2	heta}{2}$ और $\sin^2 	heta = \frac{1-\cos 2	heta}{2}$ का उपयोग करने पर:$\cos^2 252^{\circ} - \sin^2 126^{\circ} = \cos 18^{\circ} (-\sin 36^{\circ})$.$\sin^2 126^{\circ} + \sin^2 186^{\circ} + \sin^2 66^{\circ} = \frac{3}{2}$.अतः,$E = -\frac{3}{2} \sin 36^{\circ} \cos 18^{\circ} = -\frac{3\sqrt{5}}{8}$.

मान ज्ञात कीजिए: $(\cos 252^{\circ} - \sin 126^{\circ})(\cos 252^{\circ} + \sin 126^{\circ})(\sin^2 126^{\circ} + \sin^2 186^{\circ} + \sin^2 66^{\circ})$

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