Examine which of the following points are solutions of the equation $3x - 2y = 12$,and which are not:
$(1) (0, -6)$
$(2) (2, 3)$
$(3) (2, -3)$
$(4) (-4, 0)$
$(5) (-2, -9)$
$(6) (6, 4)$

(N/A) To check if a point $(x, y)$ is a solution to the equation $3x - 2y = 12$,we substitute the values of $x$ and $y$ into the equation and check if the left-hand side $(LHS)$ equals the right-hand side ($RHS$ = $12$).
$(1) (0, -6): 3(0) - 2(-6) = 0 + 12 = 12$. Since $LHS$ = $RHS$,$(0, -6)$ is a solution.
$(2) (2, 3): 3(2) - 2(3) = 6 - 6 = 0 \neq 12$. Not a solution.
$(3) (2, -3): 3(2) - 2(-3) = 6 + 6 = 12$. Since $LHS$ = $RHS$,$(2, -3)$ is a solution.
$(4) (-4, 0): 3(-4) - 2(0) = -12 - 0 = -12 \neq 12$. Not a solution.
$(5) (-2, -9): 3(-2) - 2(-9) = -6 + 18 = 12$. Since $LHS$ = $RHS$,$(-2, -9)$ is a solution.
$(6) (6, 4): 3(6) - 2(4) = 18 - 8 = 10 \neq 12$. Not a solution.
Therefore,$(1), (3),$ and $(5)$ are solutions,while $(2), (4),$ and $(6)$ are not.