Explain: Alkyl group.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) An $ \text{alkyl group} $ is a univalent radical derived from an alkane by the removal of one hydrogen atom.
The general formula for an alkane is $ C_nH_{2n+2} $.
By removing one hydrogen atom,the general formula for an alkyl group becomes $ C_nH_{2n+1} $.
These groups are often represented by the symbol $ R $.
For example,removing one hydrogen atom from methane $( CH_4 )$ results in a methyl group $( -CH_3 )$,and removing one hydrogen atom from ethane $( C_2H_6 )$ results in an ethyl group $( -C_2H_5 )$.

Explore More

Similar Questions

The relative reactivity of $1^o H$,$2^o H$,and $3^o H$ in bromination reaction has been found to be $1 : 82 : 1600$ respectively. In the reaction $CH_3-CH(CH_3)-CH_3 \text{ (excess)} + Br_2$ $\xrightarrow{hv} CH_3-C(Br)(CH_3)-CH_3 \text{ (A)} + CH_3-CH(CH_3)-CH_2-Br \text{ (B)}$,the percentage yields of the products $(A)$ and $(B)$ are expected to be:

Difficult
View Solution

Which isomer of $C_6H_{14}$ has the highest boiling point?

Select the reaction$(s)$ that would result in the formation of $2-$bromopropane.
$(I) \ CH_3-CH=CH_2 + HBr \xrightarrow{\text{peroxide}}$
$(II) \ CH_3-CH=CH_2 + HBr \xrightarrow{CCl_4}$
$(III) \ CH_3-CH_2-CH_3 + Br_2 \xrightarrow{hv}$
$(IV) \ CH_3-CH=CH_2 + Br_2 \xrightarrow{CCl_4}$

How is the iodination of alkanes performed?

The most volatile alkane is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo