Explain the origin of colour in coordination compounds.

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(N/A) When white light passes through a coordination compound,a portion of the visible spectrum is absorbed. The light that emerges is no longer white; its colour is the complementary colour of the light that was absorbed.
The complementary colour is generated from the remaining wavelengths of the visible spectrum.
For example,if a sample absorbs green light,it appears red. This phenomenon can be explained using Crystal Field Theory $(CFT)$.
Consider the complex $[Ti(H_{2}O)_{6}]^{3+}$,which is violet in colour. This complex has a $d^{1}$ configuration. The single electron occupies the $t_{2g}$ level in the ground state. Upon absorbing light,this electron undergoes a $d-d$ transition to the higher energy $e_{g}$ orbital. The energy of the absorbed photon corresponds to the crystal field splitting energy $(\Delta_{o})$,which falls within the visible region.

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Which of the following is the strongest field ligand?

The configurations of the complexes of manganese $A$ and $B$ respectively are $t_{2g}^3 e_g^1$ and $t_{2g}^4 e_g^0$. Then $A$ and $B$ are:

Crystal field stabilization energy for complex $[Co(CN)_6]^{3-}$ will be

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Match List-$I$ with List-$II$.
List-$I$ (Coordination entity) List-$II$ (Wavelength of light absorbed in $nm$)
$A$. $[CoCl(NH_3)_5]^{2+}$ $I$. $310$
$B$. $[Co(NH_3)_6]^{3+}$ $II$. $475$
$C$. $[Co(CN)_6]^{3-}$ $III$. $535$
$D$. $[Cu(H_2O)_4]^{2+}$ $IV$. $600$

Choose the correct answer from the options given below:

The number of unpaired $d$-electrons in $[Co(H_2O)_6]^{3+}$ is $\qquad$

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