Explain electrostatic potential energy difference and give the noteworthy comments on it.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) At every point in an electric field,a particle with charge $q$ possesses a certain electrostatic potential energy. The work done by an external force in moving this charge increases its potential energy by an amount equal to the potential energy difference between points $R$ and $P$.
Thus,the potential energy difference is:
$\Delta U = U_{P} - U_{R} = W_{RP}$
Therefore,we can define the electric potential energy difference between two points as the work required to be done by an external force in moving (without acceleration) a charge $q$ from one point to another within the electric field of any arbitrary charge configuration.
Following comments may be made:
$(i)$ The work done depends only on the initial and final positions of the charge. It means that the work done by an electrostatic field in moving a charge from one point to another is independent of the path taken. This is the fundamental characteristic of a conservative force.
$(ii)$ The absolute value of potential energy is not significant; only the difference in potential energy is physically significant. If we add an arbitrary constant $\alpha$ to the potential energy at every point,the difference remains unchanged: $(U_{P} + \alpha) - (U_{R} + \alpha) = U_{P} - U_{R}$.
If we define the potential energy to be zero at infinity,then the work done in bringing a charge from infinity to a point $P$ is $W_{\infty P} = U_{P}$. Thus,the potential energy of a charge $q$ at a point is defined as the work done by an external force (equal and opposite to the electric field force) in bringing the charge $q$ from infinity to that point.

Explore More

Similar Questions

As shown in the figure,charges $+q$ and $-q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex $A$ is

Two concentric hollow spheres of radii $r$ and $R$ $(R > r)$ have the same surface charge density $\sigma$. The total charge $Q$ is distributed between them. The electric potential at the common center is:

Difficult
View Solution

Two charges $q_1$ and $q_2$ are fixed at points $A$ and $B$ respectively, separated by a distance of $30 \text{ cm}$. $A$ third charge $q_3$ is moved along a circular path of radius $40 \text{ cm}$ from point $C$ to point $D$. If the difference in potential energy due to the movement of $q_3$ from $C$ to $D$ is $q_3 K / (4 \pi \epsilon_0)$, find the value of $K$. (Given: $AC = 40 \text{ cm}$, $AB = 30 \text{ cm}$, $AD = 40 \text{ cm}$)

$A$ $200 \text{ J}$ of work is done in moving a charge of $5 \text{ C}$ from a point $A$ where the potential is $-20 \text{ V}$ to another point $B$ where the potential is $V \text{ V}$. The value of $V$ at point $B$ is: (in $text{ V}$)

Two spherical conductors of radii $4 \ cm$ and $5 \ cm$ are charged to the same potential. If $\sigma_1$ and $\sigma_2$ are the respective values of the surface charge density on the two conductors,then the ratio $\sigma_1 : \sigma_2$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo