Explain the non-linear shape of $H_2S$ and the non-planar shape of $PCl_3$ using the Valence Shell Electron Pair Repulsion $(VSEPR)$ theory.
(N/A) For $H_2S$: The central atom is $S$. It has $6$ electrons in its valence shell $(_{16}S = 2, 8, 6)$.
Two electrons are shared with two $H$-atoms,and the remaining four electrons form two lone pairs.
There are a total of four electron pairs ($2$ bonding pairs and $2$ lone pairs) around the central atom.
Due to the presence of $2$ lone pairs,the electron geometry is tetrahedral,but the molecular shape is distorted,angular,or bent (non-linear).
For $PCl_3$: The central atom is $P$. It has $5$ electrons in its valence shell $(_{15}P = 2, 8, 5)$.
Three electrons are shared with three $Cl$-atoms,and the remaining two electrons form one lone pair.
There are a total of four electron pairs ($3$ bonding pairs and $1$ lone pair) around the central atom.
Due to the presence of one lone pair,the molecular shape is pyramidal (non-planar).
Two electrons are shared with two $H$-atoms,and the remaining four electrons form two lone pairs.
There are a total of four electron pairs ($2$ bonding pairs and $2$ lone pairs) around the central atom.
Due to the presence of $2$ lone pairs,the electron geometry is tetrahedral,but the molecular shape is distorted,angular,or bent (non-linear).
For $PCl_3$: The central atom is $P$. It has $5$ electrons in its valence shell $(_{15}P = 2, 8, 5)$.
Three electrons are shared with three $Cl$-atoms,and the remaining two electrons form one lone pair.
There are a total of four electron pairs ($3$ bonding pairs and $1$ lone pair) around the central atom.
Due to the presence of one lone pair,the molecular shape is pyramidal (non-planar).
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Similar Questions
Which of the following molecules has one lone pair of electrons on the central atom?
Easy
View SolutionMatch the List-$I$ with List-$II$.
List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom) $A. ICl_2^-$ $I. 4 : 2$ $B. H_2O$ $II. 4 : 1$ $C. SO_2$ $III. 2 : 3$ $D. XeF_4$ $IV. 2 : 2$
Choose the correct answer from the options given below:
| List-$I$ Molecule/ion | List-$II$ Bond pair : lone pair (on the central atom) |
| $A. ICl_2^-$ | $I. 4 : 2$ |
| $B. H_2O$ | $II. 4 : 1$ |
| $C. SO_2$ | $III. 2 : 3$ |
| $D. XeF_4$ | $IV. 2 : 2$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2025
View SolutionWhich of the following compounds has the smallest bond angle $(X - A - X)$ in each series respectively?
$(A) \ OSF_2 \ \ \ \ \ \ \ \ \ OSCl_2 \ \ \ \ \ \ \ \ \ OSBr_2$
$(B) \ SbCl_3 \ \ \ \ \ \ \ \ \ SbBr_3 \ \ \ \ \ \ \ \ \ SbI_3$
$(C) \ PI_3 \ \ \ \ \ \ \ \ \ \ \ \ AsI_3 \ \ \ \ \ \ \ \ \ \ \ \ SbI_3$
$(A) \ OSF_2 \ \ \ \ \ \ \ \ \ OSCl_2 \ \ \ \ \ \ \ \ \ OSBr_2$
$(B) \ SbCl_3 \ \ \ \ \ \ \ \ \ SbBr_3 \ \ \ \ \ \ \ \ \ SbI_3$
$(C) \ PI_3 \ \ \ \ \ \ \ \ \ \ \ \ AsI_3 \ \ \ \ \ \ \ \ \ \ \ \ SbI_3$
According to $VSEPR$ theory,in which species do all the atoms lie in the same plane?
$1.$ $CH^{+}_3$
$2.$ $CH^{-}_3$
$1.$ $CH^{+}_3$
$2.$ $CH^{-}_3$
Medium
View SolutionMatch the following List-$A$ and List-$B$ correctly.
List-$A$ List-$B$ $(1)$ $AB_3E_2$ $(A)$ $BrF_5$ $(2)$ $AB_2E_2$ $(B)$ $NH_3$ $(3)$ $AB_5E$ $(C)$ $H_2O$ $(4)$ $AB_3E$ $(D)$ $ClF_3$
| List-$A$ | List-$B$ |
| $(1)$ $AB_3E_2$ | $(A)$ $BrF_5$ |
| $(2)$ $AB_2E_2$ | $(B)$ $NH_3$ |
| $(3)$ $AB_5E$ | $(C)$ $H_2O$ |
| $(4)$ $AB_3E$ | $(D)$ $ClF_3$ |
Medium
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