Explain why cations are smaller and anions larger in radii than their parent atoms?

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(N/A) cation has fewer electrons than its parent atom,while its nuclear charge remains the same. As a result,the attraction of electrons to the nucleus is stronger in a cation than in its parent atom,leading to a smaller size.
On the other hand,an anion has more electrons than its parent atom,resulting in increased electron-electron repulsion and a decrease in the effective nuclear charge. As a result,the distance between the valence electrons and the nucleus increases,making the anion larger in radius than its parent atom.

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Among the ions $O^{2-}, Na^{+}, F^{-}, N^{3-}, Mg^{2+}$,the ions with the smallest and largest radii are respectively:

Among metals,non-metals,and noble gases,which one has the largest atomic radius? Why?

Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
The correct answer is:

Ionic radii are

What is the correct order of radii for $F, F^-, O,$ and $O^{2-}$?

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