Explain why particles of a colloidal solution do not settle down when left undisturbed,while in the case of a suspension they do.
(N/A) The particles in a colloidal solution are very small (ranging from $1 \ nm$ to $1000 \ nm$) and remain in a state of continuous random motion known as Brownian motion. This motion,along with the electrostatic repulsion between charged colloidal particles,prevents them from settling down due to gravity. In contrast,particles in a suspension are much larger (greater than $1000 \ nm$). Because of their larger size,gravity acts more effectively on them,and the intermolecular forces are not sufficient to keep them suspended,causing them to settle down when left undisturbed.
Explore More
Similar Questions
Pragya tested the solubility of four different substances at different temperatures and collected the data as given below (results are given in the following table,as grams of substance dissolved in $100 \,g$ of water to form a saturated solution).
Substance Dissolved $283 \,K$ $293 \,K$ $313 \,K$ $333 \,K$ $353 \,K$ Potassium nitrate $21$ $32$ $62$ $106$ $167$ Sodium chloride $36$ $36$ $36$ $37$ $37$ Potassium chloride $35$ $35$ $40$ $46$ $54$ Ammonium chloride $24$ $37$ $41$ $55$ $66$
$(a)$ Find the solubility of each salt at $293 \,K$. Which salt has the highest solubility at this temperature?
$(b)$ What is the effect of change of temperature on the solubility of a salt?
| Substance Dissolved | $283 \,K$ | $293 \,K$ | $313 \,K$ | $333 \,K$ | $353 \,K$ |
| Potassium nitrate | $21$ | $32$ | $62$ | $106$ | $167$ |
| Sodium chloride | $36$ | $36$ | $36$ | $37$ | $37$ |
| Potassium chloride | $35$ | $35$ | $40$ | $46$ | $54$ |
| Ammonium chloride | $24$ | $37$ | $41$ | $55$ | $66$ |
$(a)$ Find the solubility of each salt at $293 \,K$. Which salt has the highest solubility at this temperature?
$(b)$ What is the effect of change of temperature on the solubility of a salt?
Medium
View SolutionColloidal solution appears to be homogeneous but actually it is heterogeneous. Give justification for this statement.
Medium
View SolutionIdentify the solute and the solvent for the following mixtures:
$(a)$ Tincture of iodine
$(b)$ Soda water
$(c)$ Sugar solution
$(d)$ Polluted air
$(e)$ Dilute hydrochloric acid
$(a)$ Tincture of iodine
$(b)$ Soda water
$(c)$ Sugar solution
$(d)$ Polluted air
$(e)$ Dilute hydrochloric acid
Medium
View SolutionWhen is a solution said to be saturated? How can you change an unsaturated solution to a saturated solution without adding any more solute to it?
Easy
View SolutionDefine the term $solution$. Identify the solute and solvent in the following solutions:
$(i)$ Tincture of iodine
$(ii)$ Polluted air
$(iii)$ Soda water
$(iv)$ Dilute hydrochloric acid
$(i)$ Tincture of iodine
$(ii)$ Polluted air
$(iii)$ Soda water
$(iv)$ Dilute hydrochloric acid
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo