Faraday's laws of electrolysis are related to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Faraday's first law of electrolysis states that the mass $(w)$ of the substance deposited or liberated at an electrode is directly proportional to

Vedclass · Accepted Answer

Equivalent weight of the electrolyte

Vedclass · Answer

(C) Faraday's first law of electrolysis states that the mass $(w)$ of the substance deposited or liberated at an electrode is directly proportional to the quantity of electricity $(Q)$ passed through the electrolyte. Mathematically,$w = Z 	imes Q = Z 	imes i 	imes t$. Here,$Z$ is the electrochemical equivalent,which is defined as $Z = \frac{E}{F}$,where $E$ is the equivalent weight of the substance and $F$ is Faraday's constant. Therefore,$w = \frac{E 	imes i 	imes t}{F}$. Since $F$ is constant,if the current $(i)$ and time $(t)$ are kept constant,then $w \propto E$. Thus,Faraday's laws are related to the equivalent weight of the electrolyte.

Faraday's laws of electrolysis are related to the

Similar Questions

The time required (in hours) to reduce $3 \ mol$ of $Fe^{3+}$ ions to $Fe^{2+}$ ions with $2.0 \ A$ of current is $\left(1 \ F = 96500 \ C \ mol^{-1}\right)$ (in $.2$)

What is the quantity of electricity in Faradays required to produce $8 \text{ g}$ of $Mg$ (molar mass = $24 \text{ g mol}^{-1}$) from $MgCl_2$ solution (in $\text{ F}$)?

How much charge is required for the deposition of $1$ equivalent of a substance?

How many atoms of calcium will be deposited from a solution of $CaCl_2$ by a current of $0.25 \, mA$ flowing for $60 \, s$?

If the electrochemical equivalent of a substance is $0.0006735 \ g/C$,what is its equivalent weight?

Vedclass Test Series

Exam Paper Generator

Online Exam Module