Few statements are given regarding nodes in t | vedclass

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Question

(B) For any orbital,the total number of nodes is calculated as $(n - 1)$.Angular nodes are given by the azimuthal quantum number $l$.Radial nodes are

Vedclass · Accepted Answer

$ns-$orbital has $(n + 1)$ nodes.

Vedclass · Answer

(B) For any orbital,the total number of nodes is calculated as $(n - 1)$.Angular nodes are given by the azimuthal quantum number $l$.Radial nodes are given by $(n - l - 1)$.Total nodes $=$ Radial nodes $+$ Angular nodes $= (n - l - 1) + l = n - 1$.For $p_z-$orbital,the electron density is zero in the $xy-$plane,so it is a nodal plane.Therefore,the statement that $ns-$orbital has $(n + 1)$ nodes is incorrect,as it should be $(n - 1)$ nodes.

Few statements are given regarding nodes in the orbitals. Mark the statement which is not correct.

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