The figure represents the graph of photoelectric current $I$ versus applied voltage $(V)$. The maximum kinetic energy of the emitted photoelectrons is

Define saturation current,stopping potential,and cut-off frequency in the context of the photoelectric effect.

Consider the two following statements $A$ and $B$, and identify the correct choice given in the answers :
$(A)$ In photovoltaic cells, the photoelectric current produced is not proportional to the intensity of incident light.
$(B)$ In gas-filled photoemissive cells, the velocity of photoelectrons depends on the wavelength of the incident radiation.

The graph between the intensity of light $(I)$ falling on a metallic plate and the generated photoelectric current $(i)$ is:

One milliwatt of light of wavelength $4560 \ \mathring{A}$ is incident on a cesium surface of work function $1.9 \ eV$. Given that the quantum efficiency of photoelectric emission is $0.5\%$. Planck's constant $h = 6.62 \times 10^{-34} \ J \cdot s$,velocity of light $c = 3 \times 10^8 \ m/s$,the corresponding photoelectric current is:

Light of wavelength $4000 \ \mathring A$ is incident on a sodium surface,where the threshold wavelength for photoemission is $5420 \ \mathring A$. The work function of sodium is ............ $eV$.