(D) According to Faraday's law of electromagnetic induction,the induced electromotive force $(Emf)$ is given by $E = -\frac{d\phi}{dt}$.Given $\phi =

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(D) According to Faraday's law of electromagnetic induction,the induced electromotive force $(Emf)$ is given by $E = -\frac{d\phi}{dt}$.Given $\phi = 5t - 10t^2$.$E = -\frac{d}{dt}(5t - 10t^2) = -(5 - 20t)$.At $t = 0.25\, s = \frac{1}{4}\, s$,the $Emf$ is:$E = -(5 - 20 \times 0.25) = -(5 - 5) = 0\, V$.Since the induced $Emf$ is $0\, V$,the induced current $I = \frac{E}{R} = 0\, A$.

Class 12 Physics Electromagnetic Induction Faraday's and Lenz's Law

Medium

The figure shows a conducting loop placed in a magnetic field. The magnetic flux through the loop changes according to the equation $\phi = 5t - 10t^2$. What is the direction and magnitude of the induced current at $t = 0.25\, s$?

A
$0.5\, A, A \to B$
B
$0.5\, A, B \to A$
C
$1.5\, A, A \to B$
D
Zero

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Electromagnetic Induction

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Faraday's and Lenz's Law

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The figure shows a conducting loop placed in a magnetic field. The magnetic flux through the loop changes according to the equation $\phi = 5t - 10t^2$. What is the direction and magnitude of the induced current at $t = 0.25\, s$?

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