The figure shows a siphon. Choose the wrong s | vedclass

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(A) $1$. Point $1$ is at the surface of the liquid in the container,which is exposed to the atmosphere. Therefore,the pressure at point $1$ is $P_1 =

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Siphon works when $h_3 < 0$

Vedclass · Answer

(A) $1$. Point $1$ is at the surface of the liquid in the container,which is exposed to the atmosphere. Therefore,the pressure at point $1$ is $P_1 = P_0$.
$2$. Point $3$ is the exit point of the siphon,which is also exposed to the atmosphere. Therefore,the pressure at point $3$ is $P_3 = P_0$.
$3$. $A$ siphon works based on the pressure difference between the two ends. For the liquid to flow out,the exit point must be lower than the liquid level in the container,meaning $h_3 > 0$. Thus,the statement 'Siphon works when $h_3 < 0$' is incorrect.
$4$. Point $2$ is at a height $h_3$ above the exit point $3$. Using the hydrostatic pressure formula $P_3 = P_2 + \rho g h_3$,we get $P_2 = P_3 - \rho g h_3 = P_0 - \rho g h_3$.

The figure shows a siphon. Choose the wrong statement: ($P_0 =$ atmospheric pressure)

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