Figures (i) and (ii) below show the displacem | vedclass

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(C) The displacement-time equation for uniform acceleration is given by $x = x_0 + u t + \frac{1}{2} a t^2$. For a particle starting from rest $(u=0)$

Vedclass · Accepted Answer

Particle $(i)$ is having a uniformly accelerated motion while particle $(ii)$ is having a uniformly retarded motion

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(C) The displacement-time equation for uniform acceleration is given by $x = x_0 + u t + \frac{1}{2} a t^2$. For a particle starting from rest $(u=0)$,this simplifies to $x = x_0 + \frac{1}{2} a t^2$,which represents a parabolic curve. In figure $(i)$,the slope of the displacement-time graph (which represents velocity) increases with time,indicating that the particle is undergoing uniformly accelerated motion. In figure $(ii)$,the slope of the displacement-time graph decreases with time,indicating that the particle is undergoing uniformly retarded (decelerated) motion. Therefore,particle $(i)$ is having a uniformly accelerated motion while particle $(ii)$ is having a uniformly retarded motion.

Figures $(i)$ and $(ii)$ below show the displacement-time graphs of two particles moving along the x-axis. We can say that

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