Fill in the blanks in the following table:
$P(A)$ $P(B)$ $P(A \cap B)$ $P(A \cup B)$ $0.5$ $0.35$ $.........$ $0.7$
| $P(A)$ | $P(B)$ | $P(A \cap B)$ | $P(A \cup B)$ |
| $0.5$ | $0.35$ | $.........$ | $0.7$ |
- A$0.15$
- B$0.25$
- C$0.35$
- D$0.45$
Explore More
Similar Questions
In a single toss of a fair die,the odds against the event that number $4$ or $5$ turns up is
For two events $A$ and $B$,if $P(A \cup B) = 5/6$,$P(A^c) = 5/6$,and $P(B) = 2/3$,then $A$ and $B$ are
Medium
View SolutionIf $P(A \cup B) = \frac{2}{3}$,$P(A \cap B) = \frac{1}{6}$,and $P(A) = \frac{1}{3}$,then which of the following is true?
Medium
View SolutionFor two events $A$ and $B$,$P(A)=0.5$,$P(A \cup B)=0.6$ and $P(B)=K$ are given. If $A$ and $B$ are independent events,then $K=$ . . . . . . .
Given two mutually exclusive events $A$ and $B$ such that $P(A) = 0.45$ and $P(B) = 0.35,$ then $P(A \text{ or } B) =$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo