Find V_{AB} in the given circuit. | vedclass

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(A) The diode is in forward biasing,so it acts as a short circuit. The circuit can be redrawn by considering the two $10 \ \Omega$ resistors in parall

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$10 \ V$

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(A) The diode is in forward biasing,so it acts as a short circuit. The circuit can be redrawn by considering the two $10 \ \Omega$ resistors in parallel.The equivalent resistance of the two $10 \ \Omega$ resistors in parallel is $R_p = \frac{10 	imes 10}{10 + 10} = 5 \ \Omega$.Now,the circuit consists of a $30 \ V$ source in series with a $10 \ \Omega$ resistor and the equivalent resistance $R_p = 5 \ \Omega$.Using the voltage divider rule,the voltage $V_{AB}$ across the parallel combination is:$V_{AB} = \frac{R_p}{R + R_p} 	imes V_{source} = \frac{5}{10 + 5} 	imes 30 = \frac{5}{15} 	imes 30 = 10 \ V$.

Find $V_{AB}$ in the given circuit.

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