Find $p(0)$,$p(1)$,and $p(2)$ for the following polynomial: $p(x) = x^{3}$

Given polynomial is $p(x) = x^{3}$.
To find $p(0)$,substitute $x = 0$ in the polynomial:
$p(0) = (0)^{3} = 0$.
To find $p(1)$,substitute $x = 1$ in the polynomial:
$p(1) = (1)^{3} = 1$.
To find $p(2)$,substitute $x = 2$ in the polynomial:
$p(2) = (2)^{3} = 2 \times 2 \times 2 = 8$.