Find $A$,$B$ and $C$ in the following reactions:
$NH_3 + A + CO_2 \rightarrow (NH_4)_2CO_3$
$(NH_4)_2CO_3 + H_2O + B \rightarrow 2NH_4HCO_3$
$NH_4HCO_3 + NaCl \rightarrow NH_4Cl + C$
$NH_3 + A + CO_2 \rightarrow (NH_4)_2CO_3$
$(NH_4)_2CO_3 + H_2O + B \rightarrow 2NH_4HCO_3$
$NH_4HCO_3 + NaCl \rightarrow NH_4Cl + C$
- A$A - O_2; B - CO_2; C - Na_2CO_3$
- B$A - H_2O; B - O_2; C - Na_2CO_3$
- C$A - H_2O; B - O_2; C - NaHCO_3$
- D$A - H_2O; B - CO_2; C - NaHCO_3$
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