Find the equation of the circle with center at $(0,0)$ and radius $r$.
- A$x^{2} + y^{2} = r^{2}$
- B$x^{2} + y^{2} = r$
- C$x + y = r^{2}$
- D$x^{2} - y^{2} = r^{2}$
Explore More
Similar Questions
$A$ circle is drawn touching the $X$-axis,with its centre at the point of reflection of $(m, n)$ on the line $y-x=0$. Then the equation of the circle is
The circle $x^2+y^2-8x-12y+\alpha=0$ lies in the first quadrant without touching the coordinate axes. If $(6, 6)$ is an interior point to the circle,then
The power of the point $(-3, 7)$ with respect to a circle,with centre $(3, 7)$ and radius $2$,is
The centre of the circle $r^2-4r(\cos \theta+\sin \theta)-4=0$ in Cartesian coordinates is
The equation of the circle whose diameter is the diagonal of the rectangle with sides $x=4, x=-2, y=5, y=-2$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo