Find the correct pathway of water movement in | vedclass

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(C) The water potential $(\Psi_w)$ of a cell is calculated using the formula: $\Psi_w = \Psi_s + \Psi_p$.For cell $X$: $\Psi_s = -10 	ext{ bar}$, $\P

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Vedclass · Answer

(C) The water potential $(\Psi_w)$ of a cell is calculated using the formula: $\Psi_w = \Psi_s + \Psi_p$.For cell $X$: $\Psi_s = -10 	ext{ bar}$, $\Psi_p = 5 	ext{ bar}$, so $\Psi_w = -10 + 5 = -5 	ext{ bar}$.For cell $Y$: $\Psi_s = -15 	ext{ bar}$, $\Psi_p = 10 	ext{ bar}$, so $\Psi_w = -15 + 10 = -5 	ext{ bar}$.For cell $Z$: $\Psi_s = -7 	ext{ bar}$, $\Psi_p = 1 	ext{ bar}$, so $\Psi_w = -7 + 1 = -6 	ext{ bar}$.Since the water potential of $X$ and $Y$ is equal $(-5 	ext{ bar})$, there is an equilibrium between $X$ and $Y$ $(X \leftrightarrow Y)$.Water moves from a region of higher water potential to a region of lower water potential. Since $-5 	ext{ bar} > -6 	ext{ bar}$, water will flow from both $X$ and $Y$ towards $Z$ ($X 	o Z$ and $Y 	o Z$).Thus, the correct pathway is $X \leftrightarrow Y 	o Z$.

Find the correct pathway of water movement in the given presentation of cells.

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