Find the number of atoms in 39.4 g of gold. | vedclass

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(A) The number of moles $n$ is given by the formula $n = \frac{	ext{mass}}{	ext{molar mass}}$.Given mass $= 39.4 \ g$ and molar mass $= 197 \ g \ mo

Vedclass · Accepted Answer

$1.2 	imes 10^{23}$

Vedclass · Answer

(A) The number of moles $n$ is given by the formula $n = \frac{	ext{mass}}{	ext{molar mass}}$.Given mass $= 39.4 \ g$ and molar mass $= 197 \ g \ mol^{-1}$.$n = \frac{39.4}{197} = 0.2 \ mol$.The number of atoms $N$ is given by $N = n 	imes N_A$,where $N_A$ is Avogadro's number $(6.023 	imes 10^{23} \ mol^{-1})$.$N = 0.2 	imes 6.023 	imes 10^{23} = 1.2046 	imes 10^{23}$.Rounding to significant figures,the number of atoms is $1.2 	imes 10^{23}$.

Find the number of atoms in $39.4 \ g$ of gold. The molar mass of gold is $197 \ g \ mol^{-1}$.

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