Find out K_a for the acid when the degree of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The degree of hydrolysis $h$ for a salt of a weak acid and strong base is given by $h = \sqrt{\frac{K_h}{C}}$.Here,$K_h = \frac{K_w}{K_a}$,so $h =

Vedclass · Accepted Answer

$10^{-9}$

Vedclass · Answer

(B) The degree of hydrolysis $h$ for a salt of a weak acid and strong base is given by $h = \sqrt{\frac{K_h}{C}}$.Here,$K_h = \frac{K_w}{K_a}$,so $h = \sqrt{\frac{K_w}{K_a 	imes C}}$.Given $h = 1 \% = 0.01 = 10^{-2}$,$C = 0.1 \ M$,and $K_w = 10^{-14}$.Substituting the values: $10^{-2} = \sqrt{\frac{10^{-14}}{K_a 	imes 0.1}}$.Squaring both sides: $10^{-4} = \frac{10^{-14}}{K_a 	imes 0.1}$.$K_a = \frac{10^{-14}}{10^{-4} 	imes 0.1} = \frac{10^{-14}}{10^{-5}} = 10^{-9}$.

Find out $K_a$ for the acid when the degree of hydrolysis of $0.1 \ M \ CH_3COONa$ is $1 \ \%$.

Similar Questions

Aqueous solution of $CuSO_4 \cdot 5H_2O$ changes blue litmus paper to red due to:

When a salt of a weak acid and a weak base is dissolved in water at $25\,^{\circ}C$,the $pH$ of the resulting solution will always :-

Which one of the following salts on being dissolved in water gives $pH > 7$ at $25^{\circ} C$?

What is the $pH$ of a $K_2S$ solution?

The hydrolysis of sodium carbonate involves the reaction between

Vedclass Test Series

Exam Paper Generator

Online Exam Module