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Question

(A) The reaction involves the nucleophilic substitution of bromine atoms by dimethylamine $(Me_2NH)$.First,one $Me_2NH$ molecule attacks the allylic p

Vedclass · Accepted Answer

$3,4-$bis(dimethylamino)cyclopent$-1-$ene

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(A) The reaction involves the nucleophilic substitution of bromine atoms by dimethylamine $(Me_2NH)$.First,one $Me_2NH$ molecule attacks the allylic position,displacing one $Br^-$ ion.Then,the lone pair on the nitrogen atom of the newly attached dimethylamino group participates in the formation of an aziridinium ion intermediate by displacing the second $Br^-$ ion.Finally,a second molecule of $Me_2NH$ attacks the aziridinium ring,opening it to form the final product,which is $3,4$-bis(dimethylamino)cyclopent-$1$-ene.

Find out the major product formed from the following reaction. $[Me = -CH_3]$

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