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(A) The isocyanide test is a characteristic reaction for primary $(1^{\circ})$ amines. Aliphatic or aromatic primary amines,when heated with chlorofor

Vedclass · Accepted Answer

$C_6H_5CONH_2 \xrightarrow{LiAlH_4}$

Vedclass · Answer

(A) The isocyanide test is a characteristic reaction for primary $(1^{\circ})$ amines. Aliphatic or aromatic primary amines,when heated with chloroform $(CHCl_3)$ and alcoholic potassium hydroxide $(KOH)$,form isocyanides (carbylamines),which have a foul smell.In option $(A)$,benzamide $(C_6H_5CONH_2)$ is reduced by $LiAlH_4$ to form benzylamine $(C_6H_5CH_2NH_2)$,which is a primary amine. Thus,it gives a positive isocyanide test.$C_6H_5CONH_2$ $\xrightarrow{LiAlH_4} C_6H_5CH_2NH_2$ $\xrightarrow{CHCl_3 + KOH} C_6H_5CH_2NC$ (Isocyanide).$NaBH_4$ is a weaker reducing agent and does not reduce amides to amines. Option $(C)$ involves the reduction of an $N$-substituted amide,which would yield a secondary amine,not a primary amine.

Find out the reaction in which the obtained product gives a positive isocyanide test.

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