Find the LCM and HCF of the following pairs o | vedclass

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(A) First,find the prime factorization of the given numbers:$26 = 2 	imes 13$$91 = 7 	imes 13$The $HCF$ is the product of the smallest power of each

Vedclass · Accepted Answer

$2366$

Vedclass · Answer

(A) First,find the prime factorization of the given numbers:$26 = 2 	imes 13$$91 = 7 	imes 13$The $HCF$ is the product of the smallest power of each common prime factor:$HCF = 13$The $LCM$ is the product of the greatest power of each prime factor involved:$LCM = 2 	imes 7 	imes 13 = 182$Now,verify the relationship:Product of the two numbers $= 26 	imes 91 = 2366$$HCF 	imes LCM = 13 	imes 182 = 2366$Since $2366 = 2366$,the relationship $LCM 	imes HCF =$ product of the two numbers is verified.

Find the $LCM$ and $HCF$ of the following pairs of integers and verify that $LCM \times HCF =$ product of the two numbers $26$ and $91$.

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