Find the LCM and HCF of the following pairs o | vedclass

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(C) First,find the prime factorization of the numbers:$336 = 2^4 	imes 3 	imes 7$$54 = 2 	imes 3^3$$HCF$ is the product of the smallest power of ea

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$18144$

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(C) First,find the prime factorization of the numbers:$336 = 2^4 	imes 3 	imes 7$$54 = 2 	imes 3^3$$HCF$ is the product of the smallest power of each common prime factor:$HCF = 2^1 	imes 3^1 = 6$$LCM$ is the product of the greatest power of each prime factor involved:$LCM = 2^4 	imes 3^3 	imes 7 = 16 	imes 27 	imes 7 = 3024$Now,verify the relationship:Product of the two numbers $= 336 	imes 54 = 18144$$LCM 	imes HCF = 3024 	imes 6 = 18144$Since $18144 = 18144$,the relationship is verified.

Find the $LCM$ and $HCF$ of the following pairs of integers and verify that $LCM \times HCF =$ product of the two numbers $336$ and $54$.

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