Find the 12^{text{th}} term from the end of t | vedclass

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Question

(A) Given $AP: -2, -4, -6, \ldots, -100$.Here,the first term $(a) = -2$,the common difference $(d) = -4 - (-2) = -2$,and the last term $(l) = -100$.We

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$-78$

Vedclass · Answer

(A) Given $AP: -2, -4, -6, \ldots, -100$.Here,the first term $(a) = -2$,the common difference $(d) = -4 - (-2) = -2$,and the last term $(l) = -100$.We know that the $n^{	ext{th}}$ term of an $AP$ from the end is given by the formula $a_n = l - (n - 1)d$,where $l$ is the last term and $d$ is the common difference.Therefore,the $12^{	ext{th}}$ term from the end is:$a_{12} = -100 - (12 - 1)(-2)$$a_{12} = -100 - (11)(-2)$$a_{12} = -100 + 22$$a_{12} = -78$.Hence,the $12^{	ext{th}}$ term from the end is $-78$.

Find the $12^{\text{th}}$ term from the end of the $AP: -2, -4, -6, \ldots, -100$.

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