Find the 10^{th} term of the A.P. sqrt{2}, 3 | vedclass

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(C) The given $A.P.$ is $\sqrt{2}, 3 \sqrt{2}, 5 \sqrt{2}, \ldots$Here,the first term $a = \sqrt{2}$.The common difference $d = 3 \sqrt{2} - \sqrt{2}

Vedclass · Accepted Answer

$19$

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(C) The given $A.P.$ is $\sqrt{2}, 3 \sqrt{2}, 5 \sqrt{2}, \ldots$Here,the first term $a = \sqrt{2}$.The common difference $d = 3 \sqrt{2} - \sqrt{2} = 2 \sqrt{2}$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.For the $10^{th}$ term $(n = 10)$:$a_{10} = \sqrt{2} + (10 - 1)(2 \sqrt{2})$$a_{10} = \sqrt{2} + 9(2 \sqrt{2})$$a_{10} = \sqrt{2} + 18 \sqrt{2}$$a_{10} = 19 \sqrt{2}$.

Find the $10^{th}$ term of the $A.P.$ $\sqrt{2}, 3 \sqrt{2}, 5 \sqrt{2}, \ldots$ (in $\sqrt{2}$)

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