Class 12PhysicsDual Nature of Radiation and MatterEinstein's Photoelectric Equation and Energy Quantum of Radiation
EasyFind the correct statement$(s)$ about the photoelectric effect.
- AThere is no significant time delay between the absorption of suitable radiation and the emission of electrons.
- BEinstein's analysis gives a threshold frequency below which no electron can be emitted.
- CThe maximum kinetic energy of the emitted photoelectrons is directly proportional to the frequency of incident radiation.
- DThe maximum kinetic energy of electrons does not depend on the intensity of radiation.
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The maximum kinetic energy of a photoelectron liberated from the surface of lithium with work function $2.35 \text{ eV}$ by electromagnetic radiation whose electric component varies with time as: $E=a[1+\cos(2 \pi f_1 t)] \cos(2 \pi f_2 t)$ (where $a$ is a constant) is (given $f_1=3.6 \times 10^{15} \text{ Hz}$,$f_2=1.2 \times 10^{15} \text{ Hz}$ and Planck's constant $h=6.6 \times 10^{-34} \text{ Js}$) (in $\text{ eV}$)
DifficultAP EAMCET 2019
View Solution$A$ photoelectric surface is illuminated successively by monochromatic light of wavelength $\lambda$ and $\lambda /2$. If the maximum kinetic energy of the emitted photoelectrons in the second case is $3$ times that in the first case,the work function of the surface of the material is
$(h =$ Planck's constant,$c =$ speed of light $)$
$(h =$ Planck's constant,$c =$ speed of light $)$
DifficultJEE MAIN 2016
View SolutionPhotons with energy $5\, eV$ are incident on a cathode $C$ of a photoelectric cell. The maximum kinetic energy of the emitted photoelectrons is $2\, eV$. When photons of energy $6\, eV$ are incident on $C$,no photoelectrons will reach the anode $A$ if the stopping potential of $A$ relative to $C$ is .............. $V$.
Medium
View SolutionThe threshold frequency of a photosensitive material is equal to the frequency of the $H_{\alpha}$ line of hydrogen. If a photon whose frequency is equal to the frequency of the $H_{\beta}$ line of hydrogen is incident on this photosensitive material,the maximum kinetic energy of the emitted photoelectrons is ($R$ = Rydberg's constant,$h$ = Planck's constant,and $c$ = speed of light in vacuum).
When a point source of light is at a distance of $50 \, cm$ from a photoelectric cell,the cut-off voltage is found to be $V_0$. If the same source is placed at a distance of $1 \, m$ from the cell,then the cut-off voltage will be
Easy
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