Find the derivative of the function $f(x) = x^{4}(5 \sin x - 3 \cos x)$ with respect to $x$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Let $f(x) = x^{4}(5 \sin x - 3 \cos x)$.
Using the product rule,$\frac{d}{dx}[u(x)v(x)] = u(x)v'(x) + v(x)u'(x)$:
$f'(x) = x^{4} \frac{d}{dx}(5 \sin x - 3 \cos x) + (5 \sin x - 3 \cos x) \frac{d}{dx}(x^{4})$
$f'(x) = x^{4}(5 \cos x - 3(-\sin x)) + (5 \sin x - 3 \cos x)(4x^{3})$
$f'(x) = x^{4}(5 \cos x + 3 \sin x) + 4x^{3}(5 \sin x - 3 \cos x)$
$f'(x) = 5x^{4} \cos x + 3x^{4} \sin x + 20x^{3} \sin x - 12x^{3} \cos x$
Factoring out $x^{3}$:
$f'(x) = x^{3}(5x \cos x + 3x \sin x + 20 \sin x - 12 \cos x)$

Explore More

Similar Questions

Evaluate: $\frac{d}{d x}\left[e^{\tan ^{-1} x+\cot ^{-1} x}+\frac{x}{2} \sqrt{a^2-x^2}+\frac{a^2}{2} \sin ^{-1} \frac{x}{a}\right]$

If $f(1) = 1$ and $f'(1) = 3$,then the derivative of $f(f(f(x))) + (f(x))^2$ at $x = 1$ is:

Find the derivative of the following function: $5 \sec x + 4 \cos x$.

If $y = \cos^{-1}(\tanh x) + \sinh(\sin 6x)$, then $\frac{dy}{dx} =$

If $f(x) = \cos^{-1} x$,$g(x) = e^x$,and $h(x) = g(f(x))$,then $\frac{h'(x)}{h(x)} = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo