Find the direction of vibration of the electric field if the vibration of the magnetic field is in the positive $x-$ axis and the propagation of the electromagnetic wave is along the positive $y-$ axis.

The magnetic field in a plane electromagnetic wave is given by $\vec B = B_0 \sin(kx + \omega t) \hat j \ T$. The expression for the corresponding electric field will be (where $c$ is the speed of light).

The magnetic field of a plane electromagnetic wave is given by $\overrightarrow{ B } = 2 \times 10^{-8} \sin (0.5 \times 10^{3} x + 1.5 \times 10^{11} t) \hat{ j } \text{ T}$. The amplitude of the electric field would be:

Electromagnetic waves with frequencies ranging from $2\,\text{MHz}$ to $30\,\text{MHz}$ are propagated by:

$A$ plane polarized monochromatic $EM$ wave is travelling in a vacuum along the $z$-direction such that at $t = t_1$,it is found that the electric field is zero at a spatial point $z_1$. The next zero that occurs in its neighborhood is at $z_2$. The frequency of the electromagnetic wave is:

The electric field and magnetic field components of an electromagnetic wave going through vacuum are described by
$E_x = E_0 \sin(kz - \omega t)$
$B_y = B_0 \sin(kz - \omega t)$
Then the correct relation between $E_0$ and $B_0$ is given by