Find the equation for the ellipse that satisf | vedclass

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(A) The ends of the major axis are $(\pm 3, 0)$,which implies the major axis lies along the $x$-axis and $a = 3$.The ends of the minor axis are $(0, \

Vedclass · Accepted Answer

$\frac{x^2}{9} + \frac{y^2}{4} = 1$

Vedclass · Answer

(A) The ends of the major axis are $(\pm 3, 0)$,which implies the major axis lies along the $x$-axis and $a = 3$.The ends of the minor axis are $(0, \pm 2)$,which implies $b = 2$.The standard equation of an ellipse with the major axis along the $x$-axis is $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$.Substituting the values $a = 3$ and $b = 2$,we get $\frac{x^2}{3^2} + \frac{y^2}{2^2} = 1$.Therefore,the equation is $\frac{x^2}{9} + \frac{y^2}{4} = 1$.

Find the equation for the ellipse that satisfies the given conditions: Ends of major axis $(\pm 3, 0)$,ends of minor axis $(0, \pm 2)$.

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