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(B) The given circuit can be simplified by identifying the series combinations of resistors.Looking at the circuit,the $4\,\Omega$ and $8\,\Omega$ res

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$4$

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(B) The given circuit can be simplified by identifying the series combinations of resistors.Looking at the circuit,the $4\,\Omega$ and $8\,\Omega$ resistors are in series,forming an equivalent resistance of $4 + 8 = 12\,\Omega$.Similarly,the $2\,\Omega$ and $4\,\Omega$ resistors are in series,forming an equivalent resistance of $2 + 4 = 6\,\Omega$.These two branches are connected in parallel between points $a$ and $b$.The equivalent resistance $R_{ab}$ is given by:$R_{ab} = \frac{12 	imes 6}{12 + 6} = \frac{72}{18} = 4\,\Omega$.

Find the equivalent resistance between the points $a$ and $b$ in $\Omega$.

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