Find the following integral: int left(x^{frac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We use the power rule for integration,which states that $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ for $n 
eq -1$.$\int \left(x^{\frac{2}{3}} + 1i

Vedclass · Accepted Answer

$\frac{3}{5} x^{\frac{5}{3}} + x + C$

Vedclass · Answer

(A) We use the power rule for integration,which states that $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ for $n 
eq -1$.$\int \left(x^{\frac{2}{3}} + 1ight) dx = \int x^{\frac{2}{3}} dx + \int 1 dx$$= \frac{x^{\frac{2}{3} + 1}}{\frac{2}{3} + 1} + x + C$$= \frac{x^{\frac{5}{3}}}{\frac{5}{3}} + x + C$$= \frac{3}{5} x^{\frac{5}{3}} + x + C$

Find the following integral: $\int \left(x^{\frac{2}{3}} + 1\right) dx$

Similar Questions

Find the integral of the function $\sin ^{2}(2 x+5)$.

$\int (\tan x - \cot x)^2 \, dx = $

$\int \frac{\sin 3x}{\sin x} \, dx = $

$\int \frac{1}{\sqrt{8+2x-x^2}} dx =$

If $x \notin [2n\pi - \frac{\pi}{4}, 2n\pi + \frac{3\pi}{4}]$ and $n \in Z$,then $\int \sqrt{1 - \sin 2x} \, dx = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module