Find the greatest number that will divide $390, 495,$ and $300$ without leaving a remainder.

  • A
    $5$
  • B
    $15$
  • C
    $25$
  • D
    $35$

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Determine the $L.C.M.$ of $\frac{2}{5}, \frac{3}{10}$ and $\frac{6}{25}$.

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The $LCM$ of $2^{2} \times 3^{2} \times 5 \times 11$,$2^{4} \times 3^{4} \times 5^{2} \times 7$,and $2^{5} \times 3^{3} \times 5^{2} \times 7^{2} \times 11$ is:

What will be the least number which when doubled will be exactly divisible by $12, 18, 21$ and $30$?

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