Find the inverse of the matrix $A = \left[\begin{array}{ll}2 & 3 \\ 5 & 7\end{array}\right]$,if it exists.

  • A
    $A^{-1} = \left[\begin{array}{cc}-7 & 3 \\ 5 & -2\end{array}\right]$
  • B
    $A^{-1} = \left[\begin{array}{cc}7 & -3 \\ -5 & 2\end{array}\right]$
  • C
    $A^{-1} = \left[\begin{array}{cc}-7 & -3 \\ -5 & -2\end{array}\right]$
  • D
    $A^{-1} = \left[\begin{array}{cc}7 & 3 \\ 5 & 2\end{array}\right]$

Explore More

Similar Questions

If $A=\begin{bmatrix} 1 & 0 & -2 \\ -2 & -1 & 2 \\ 3 & 4 & 1 \end{bmatrix}$,then $A^{-1}=$

If $A = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 1 & 1 \\ 1 & 3 & 1 \end{bmatrix}$ and $B = \begin{bmatrix} 2 & 3 & 4 \\ 3 & 2 & 2 \\ 2 & 4 & 2 \end{bmatrix}$, then $\sqrt{|\operatorname{Adj}(AB)|} = $

If $A$ is a non-singular matrix such that $(A-2I)(A-4I)=0$,then $A+8A^{-1} = \_\_\_\_$

If $B = \begin{bmatrix} 1 & \alpha & 2 \\ 1 & 2 & 2 \\ 2 & 3 & 3 \end{bmatrix}$ is the adjoint of a $3 \times 3$ matrix $A$ and $|A| = 5$,then $\alpha$ is equal to

The inverse of $\begin{bmatrix} 1 & 2 & 3 \\ 0 & 1 & 2 \\ 0 & 0 & 1 \end{bmatrix}$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo