Find the least number of six digits which is | vedclass

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(C) First,find the $L.C.M.$ of $15, 21$ and $28$.$15 = 3 	imes 5$$21 = 3 	imes 7$$28 = 2^2 	imes 7$$L.C.M. = 2^2 	imes 3 	imes 5 	imes 7 = 4 	i

Vedclass · Accepted Answer

$100380$

Vedclass · Answer

(C) First,find the $L.C.M.$ of $15, 21$ and $28$.$15 = 3 	imes 5$$21 = 3 	imes 7$$28 = 2^2 	imes 7$$L.C.M. = 2^2 	imes 3 	imes 5 	imes 7 = 4 	imes 3 	imes 5 	imes 7 = 420$.The smallest $6$-digit number is $100000$.Divide $100000$ by $420$ to find the remainder:$100000 \div 420 = 238$ with a remainder of $40$.To find the least $6$-digit number exactly divisible by $420$,we add the difference between the divisor and the remainder to the smallest $6$-digit number:Required number $= 100000 + (420 - 40) = 100000 + 380 = 100380$.

Find the least number of six digits which is exactly divisible by $15, 21$ and $28$.

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