Find the major product in the given reaction:

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(B) The reaction of an ether with $HI$ proceeds via an $SN^1$ mechanism when one of the alkyl groups is tertiary. $1$. The oxygen atom of the ether is

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$CH_3-CH_2-CH_2-OH$ and $CH_3-CH_2-C(CH_3)_2-I$

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(B) The reaction of an ether with $HI$ proceeds via an $SN^1$ mechanism when one of the alkyl groups is tertiary. $1$. The oxygen atom of the ether is protonated by $H^+$ from $HI$ to form an oxonium ion. $2$. The bond between the oxygen and the tertiary carbon breaks to form a stable tertiary carbocation $(CH_3-CH_2-C^+(CH_3)_2)$ and a propanol molecule $(CH_3-CH_2-CH_2-OH)$. $3$. The iodide ion $(I^-)$ then attacks the tertiary carbocation to form the tertiary alkyl iodide $(CH_3-CH_2-C(CH_3)_2-I)$. Thus,the products are $CH_3-CH_2-CH_2-OH$ and $CH_3-CH_2-C(CH_3)_2-I$.

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