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Question

(C) The reaction between Benzaldehyde $(C_6H_5CHO)$ and Acetaldehyde $(CH_3CHO)$ in the presence of a base $(Ca(OH)_2)$ and heating is a Claisen-Schmi

Vedclass · Accepted Answer

$C_6H_5-CH=CH-CHO$

Vedclass · Answer

(C) The reaction between Benzaldehyde $(C_6H_5CHO)$ and Acetaldehyde $(CH_3CHO)$ in the presence of a base $(Ca(OH)_2)$ and heating is a Claisen-Schmidt condensation (a type of Cross-Aldol condensation).Benzaldehyde lacks $\alpha$-hydrogens,so the enolate ion is formed from acetaldehyde.The enolate ion attacks the carbonyl carbon of benzaldehyde to form an aldol intermediate,which subsequently undergoes dehydration upon heating to yield the $\alpha,\beta$-unsaturated aldehyde,Cinnamaldehyde $(C_6H_5-CH=CH-CHO)$.

Find the major product of the following reaction: $C_6H_5CHO + CH_3CHO \xrightarrow{Ca(OH)_2, \Delta} ?$

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