Find the mode of the following frequency dist | vedclass

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(D) To find the mode of a grouped frequency distribution,we use the formula:$Mode = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$$1$

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(D) To find the mode of a grouped frequency distribution,we use the formula:$Mode = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$$1$. Identify the modal class (the class with the highest frequency). Here,the highest frequency is $55$,which corresponds to the class interval $60-70$.$2$. From the modal class:Lower limit $(l)$ = $60$Frequency of the modal class $(f_1)$ = $55$Frequency of the class preceding the modal class $(f_0)$ = $43$Frequency of the class succeeding the modal class $(f_2)$ = $37$Class size $(h)$ = $70 - 60 = 10$$3$. Substitute the values into the formula:$Mode = 60 + \left( \frac{55 - 43}{2(55) - 43 - 37} ight) 	imes 10$$Mode = 60 + \left( \frac{12}{110 - 80} ight) 	imes 10$$Mode = 60 + \left( \frac{12}{30} ight) 	imes 10$$Mode = 60 + \left( \frac{12}{3} ight)$$Mode = 60 + 4 = 64$Therefore,the mode of the given frequency distribution is $64$.

Class	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$
Frequency	$8$	$12$	$27$	$43$	$55$	$37$	$18$

Class	$0-100$	$100-200$	$200-300$	$300-400$	$400-500$	$500-600$
Frequency	$12$	$18$	$27$	$20$	$17$	$6$

Class	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$
Frequency	$8$	$12$	$27$	$x$	$55$	$37$	$y$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$6$	$8$	$17$	$x$	$42$	$30$	$y$	$8$

Find the mode of the following frequency distribution:

Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$

Frequency $8$ $12$ $27$ $43$ $55$ $37$ $18$

Similar Questions

Find the mode of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $6$ $8$ $17$ $24$ $42$ $30$ $15$ $8$

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{0} = \ldots \ldots \ldots$

For the calculation of mode of the following frequency distribution,$f_{1} = \dots \dots \dots \dots \dots \dots$

Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$

Frequency $12$ $18$ $27$ $20$ $17$ $6$

The mode of the following frequency distribution is $64$ and the total frequency is $200.$ Find the missing frequencies $x$ and $y.$

Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$

Frequency $8$ $12$ $27$ $x$ $55$ $37$ $y$

The mode of the following frequency distribution is $46$ and the total frequency is $150$. Find the missing frequencies $x$ and $y$.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $6$ $8$ $17$ $x$ $42$ $30$ $y$ $8$

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Find the mode of the following frequency distribution: Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$ Frequency $8$ $12$ $27$ $43$ $55$ $37$ $18$