Find the number of terms in the finite A.P. 7 | vedclass

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(D) The given $A.P.$ is $7, 11, 15, \ldots, 107$.Here,the first term $a = 7$.The common difference $d = 11 - 7 = 4$.The last term $a_n = 107$.The form

Vedclass · Accepted Answer

$26$

Vedclass · Answer

(D) The given $A.P.$ is $7, 11, 15, \ldots, 107$.Here,the first term $a = 7$.The common difference $d = 11 - 7 = 4$.The last term $a_n = 107$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values: $107 = 7 + (n - 1)4$.$107 - 7 = (n - 1)4$.$100 = (n - 1)4$.$n - 1 = 100 / 4 = 25$.$n = 25 + 1 = 26$.Therefore,the number of terms in the $A.P.$ is $26$.

Find the number of terms in the finite $A.P.$ $7, 11, 15, \ldots, 107$.

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