Find the odd man out:190, 166, 145, 128, 112, | vedclass

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Question

(C) Let us analyze the differences between consecutive terms:$190 - 166 = 24$$166 - 145 = 21$$145 - 128 = 17$$128 - 112 = 16$$112 - 100 = 12$$100 - 91

Vedclass · Accepted Answer

$128$

Vedclass · Answer

(C) Let us analyze the differences between consecutive terms:$190 - 166 = 24$$166 - 145 = 21$$145 - 128 = 17$$128 - 112 = 16$$112 - 100 = 12$$100 - 91 = 9$Now,let us look at the differences of the differences:$24 - 21 = 3$$21 - 17 = 4$$17 - 16 = 1$The pattern of differences should ideally be a decreasing sequence like $24, 21, 18, 15, 12, 9$. If we replace $128$ with $127$,the sequence becomes $190, 166, 145, 127, 112, 100, 91$.The differences would then be:$190 - 166 = 24$$166 - 145 = 21$$145 - 127 = 18$$127 - 112 = 15$$112 - 100 = 12$$100 - 91 = 9$This forms a consistent pattern where the difference decreases by $3$ each time.Therefore,$128$ is the odd man out.

$15$	$16$	$25$	$50$
$189$	$(a)$	$(b)$	$(c)$	$(d)$	$(e)$

Find the odd man out:
$190, 166, 145, 128, 112, 100, 91$

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Find the odd man out:$190, 166, 145, 128, 112, 100, 91$