Find the osmotic pressure of a 0.01 text{ M} | vedclass

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(B) The formula for osmotic pressure $(\pi)$ is $\pi = CRT$.Given:Concentration $C = 0.01 	ext{ M} = 0.01 	ext{ mol L}^{-1}$.Temperature $T = 25 	e

Vedclass · Accepted Answer

$0.245$

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(B) The formula for osmotic pressure $(\pi)$ is $\pi = CRT$.Given:Concentration $C = 0.01 	ext{ M} = 0.01 	ext{ mol L}^{-1}$.Temperature $T = 25 	ext{ }^\circ	ext{C} = 25 + 273 = 298 	ext{ K}$.Gas constant $R = 0.0821 	ext{ L atm mol}^{-1} 	ext{K}^{-1}$.Substituting the values:$\pi = 0.01 	ext{ mol L}^{-1} 	imes 0.0821 	ext{ L atm mol}^{-1} 	ext{K}^{-1} 	imes 298 	ext{ K}$.$\pi = 0.01 	imes 24.4658 	ext{ atm}$.$\pi = 0.244658 	ext{ atm} \approx 0.245 	ext{ atm}$.

Find the osmotic pressure of a $0.01 \text{ M}$ solution at $25 \text{ }^\circ\text{C}$ $(R = 0.0821 \text{ L atm mol}^{-1} \text{K}^{-1})$. (in $\text{ atm}$)

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