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(C) The circuit consists of two parallel blocks connected in series with a $10 \Omega$ resistor.First,calculate the equivalent resistance of the top p

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$213$

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(C) The circuit consists of two parallel blocks connected in series with a $10 \Omega$ resistor.First,calculate the equivalent resistance of the top parallel block ($15 \Omega$ and $5 \Omega$):$R_{eq1} = \frac{15 	imes 5}{15 + 5} = \frac{75}{20} = 3.75 \Omega$.The voltage across this block is given as $45 V$. The current $I$ flowing through this branch is:$I = \frac{V}{R_{eq1}} = \frac{45}{3.75} = 12 A$.Next,calculate the equivalent resistance of the middle parallel block $(24 \Omega, 12 \Omega, 8 \Omega)$:$\frac{1}{R_{eq2}} = \frac{1}{24} + \frac{1}{12} + \frac{1}{8} = \frac{1 + 2 + 3}{24} = \frac{6}{24} = \frac{1}{4} \Rightarrow R_{eq2} = 4 \Omega$.The total potential difference between $a$ and $b$ is the sum of the potential drops across the three sections:$V_{ab} = V_{top} + V_{middle} + V_{bottom} = 45 V + (I 	imes R_{eq2}) + (I 	imes 10 \Omega)$.$V_{ab} = 45 + (12 	imes 4) + (12 	imes 10) = 45 + 48 + 120 = 213 V$.

Find the potential difference between $a$ and $b$,as shown in the below circuit. (in $V$)

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