Find the principal value of cos ^{-1}left(fra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $y = \cos^{-1}\left(\frac{\sqrt{3}}{2}\right)$.Then,$\cos y = \frac{\sqrt{3}}{2}$.We know that $\cos\left(\frac{\pi}{6}\right) = \frac{\sqrt{3

Vedclass · Accepted Answer

$\frac{\pi}{6}$

Vedclass · Answer

(D) Let $y = \cos^{-1}\left(\frac{\sqrt{3}}{2}\right)$.Then,$\cos y = \frac{\sqrt{3}}{2}$.We know that $\cos\left(\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2}$.The range of the principal value branch of $\cos^{-1} x$ is $[0, \pi]$.Since $\frac{\pi}{6} \in [0, \pi]$,the principal value of $\cos^{-1}\left(\frac{\sqrt{3}}{2}\right)$ is $\frac{\pi}{6}$.

Find the principal value of $\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)$.

Similar Questions

The value of $\cos^{-1}(\cos \frac{5\pi}{3}) + \sin^{-1}(\sin \frac{5\pi}{3})$ is

The principal value of $\sin ^{-1}\left(\sin \left(\frac{2 \pi}{3}\right)\right)$ is

If $\sin^{-1} \theta = \sin^{-1}(\sin 5)$,then $\theta$ is

The simplest form of $\cot ^{-1}\left(\frac{1}{\sqrt{x^2-1}}\right), x>1$ is . . . . . . .

Solve $\tan ^{-1} 2 x+\tan ^{-1} 3 x=\frac{\pi}{4}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module