Find the range of the following function:
$f(x) = x^{2} + 2$,where $x$ is a real number.

(N/A) Given the function $f(x) = x^{2} + 2$,where $x \in \mathbb{R}$.
Since $x$ is a real number,the square of any real number is always non-negative:
$x^{2} \geq 0$
Adding $2$ to both sides of the inequality:
$x^{2} + 2 \geq 0 + 2$
$x^{2} + 2 \geq 2$
Since $f(x) = x^{2} + 2$,we have:
$f(x) \geq 2$
Therefore,the range of the function $f$ is the set of all real numbers greater than or equal to $2$.
In interval notation,the range is $[2, \infty)$.