Find the resistance of a bulb rated as 100 , | vedclass

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(A) The power $P$ and voltage $V$ are given as $P = 100 \, W$ and $V = 250 \, V$. Using the formula for electrical power,$P = \frac{V^2}{R}$,we can re

Vedclass · Accepted Answer

$625 \, \Omega$

Vedclass · Answer

(A) The power $P$ and voltage $V$ are given as $P = 100 \, W$ and $V = 250 \, V$. Using the formula for electrical power,$P = \frac{V^2}{R}$,we can rearrange it to solve for resistance $R$: $R = \frac{V^2}{P}$. Substituting the given values: $R = \frac{250 	imes 250}{100} = \frac{62500}{100} = 625 \, \Omega$. Therefore,the resistance of the bulb is $625 \, \Omega$.

Find the resistance of a bulb rated as $100 \, W - 250 \, V$.

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